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Proof step 1 from proof lemma-ax2 (conclusion)

⊦ 2^(n + 1) = 2 * 2^ n

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 2:
⊦ m +1 = m + 1
Proof step 3:
n +1 = n + 1 ⊦ 2^(n + 1) = 2 * 2^ n

Rule argument

spec: nat-basic2 inst: name: succ seq: ⊦ m +1 = m + 1 subst: [m] → [n] flags:

Additional information

Used terms: n