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Proof step 6 from proof lsucc-01 (previous step)

⊦ 2 ^ log2 n ≤ n, log2(2 * n + 1) = log2 n + 1, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
n < 2 ^ log2 n ⊦ n = 0, log2(2 * n + 1) = log2 n + 1

Rule argument

Additional information

Used simplifier rules: two-pot-zero: ⊦ 2 ^ n ≠ 0;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat