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Proof step 9 from proof lsucc-01 (previous step)

n ≠ 0 → ¬ n < 2^ log2 n, n < 2 ^ log2 n ⊦ n = 0, log2(2 * n + 1) = log2 n + 1

User applied rule case distinction

And obtained the following new goals

Proof step 10:
¬ n < 2^ log2 n, n < 2 ^ log2 n ⊦ n = 0, log2(2 * n + 1) = log2 n + 1

Rule argument

pos: left 1

Additional information