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Proof step 16 from proof ltwo-03 (previous step)

n < 2 * 2^ log2 n, 4 * 2 ^ log2 n ≤ 2 * n ⊦ log2(2 * n) = log2 n + 1, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
n < 2 * 2 ^ log2 n, 4 * 2 ^ log2 n ≤ 2 * n ⊦ n = 0, log2(2 * n) = log2 n + 1

Rule argument

Additional information

Used simplifier rules: pot2-def: ⊦ 2^ m = 2 ^ m;%two-pot-zero: ⊦ 2 ^ n ≠ 0;%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%two-zero-01: ⊦ 2 * m = 0 ↔ m = 0; from specification nat-mult%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1