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Proof step 1 from proof ltwo-04 (conclusion)

⊦ log2 2 = 1

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ 2^ m ≤ n ∧ n < 2^ m +1 → log2 n = m
Proof step 3:
2^ 1 ≤ 2 ∧ 2 < 2^ 1 +1 → log2 2 = 1 ⊦ log2 2 = 1

Rule argument

spec: nat-pot inst: name: Log2def seq: ⊦ 2^ m ≤ n ∧ n < 2^ m +1 → log2 n = m subst: [m, n] → [1, 2] flags: current, []

Additional information

Used terms: 1, 2