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Proof step 3 from proof pot-01 (previous step)

2^(n -1 + 1) = 2 * 2^ n -1, n ≠ 0 ⊦ 2 * 2^ n -1 = 2^ n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ n = 0, 2 * 2^(n - 1) = 2^ n

Rule argument

Additional information

Used simplifier rules: lemma-ax2: ⊦ 2^(n + 1) = 2 * 2^ n;%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%pred-03: ⊦ n -1 = n - 1; from specification nat