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Proof step 3 from proof potmonleq (previous step)

2^ m ≤ 2^ n, n < m ⊦ n = m, m = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
2^ n < 2^ m, 2^ m ≤ 2^ n, n < m ⊦ n = m, m = 0

Rule argument

fma: 2^ n < 2^ m

Additional information

Used simplifier rules: potmon: ⊦ 2^ m < 2^ n ↔ m < n;%neq-01: ⊦ m ≠ n → (¬ m < n ↔ n < m); from specification nat-basic1%ls-02: ⊦ m < n → ¬ n < m; from specification nat-basic1 Used formulas: 2^ n < 2^ m