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Proof step 4 from proof power-of-2-01 (previous step)

⊦ 2 ^ m = 1, n = 0, (2 * 2) * 2 ^ m / 2 = 2 * 2 ^ m

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ m0 * m * n = (m0 * m) * n
Proof step 6:
⊦ 2 ^ m = 1, n = 0, 2 * 2 * 2 ^ m / 2 = 2 * 2 ^ m

Rule argument

spec: nat-mult inst: name: mult-a seq: ⊦ m0 * m * n = (m0 * m) * n subst: [n, m, m0] → [2 ^ m / 2, 2, 2] flags: rewrite

Additional information

Used terms: 2 ^ m / 2, 2, 2