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Proof step 23 from proof cong-equiv (previous step)

m0 * m < m1 * m, n1 + m1 * m = m0 * m, m0 < m1, n2 < m ⊦ m * (m0 - m1) = n1, n1 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: rotate, discard

Additional information

Used simplifier rules: l-02: ⊦ ¬ m + n < m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2