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Proof step 24 from proof cong-equiv (previous step)

m1 ≤ m0, n1 + m1 * m = m0 * m, n2 < m ⊦ n1 = 0, m0 * m - m1 * m = n1

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: rotate, discard

Additional information

Used simplifier rules: eq-01: ⊦ m + n - m = n; from specification nat%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2