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Proof step 1 from proof div (conclusion)

⊦ prime(m) ∧ n ≠ 1 → (n | m ↔ n = m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
prime(m), n | m ⊦ n = 1, n = m

Rule argument

Additional information

Used simplifier rules: divi-ref: ⊦ m | m;