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Proof step 5 from proof div (
previous step
)
n | m, ∀ m0. m0 | m → m0 = 1 ∨ m0 = m ⊦ n = 1, n = m, m = 1, m = 0
User applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: n abort: F discard: T computed: T
Additional information
Used terms: n