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Proof step 1 from proof divi-eq (conclusion)

m | n, n | m ⊦ m = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ m | n ↔ (∃ n0. m * n0 = n)
Proof step 3:
∃ n0. m * n0 = n, n | m ⊦ m = n

Rule argument

spec: nat-prime inst: name: Divides seq: ⊦ m | n ↔ (∃ n0. m * n0 = n) subst: [n, m] → [n, m] flags: rewrite, current

Additional information

Used terms: n, m