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Proof step 3 from proof divi-primmult (
previous step
)
gcd(m, n) = 1, prime(m), m | n * n0 ⊦ m | n, m | n0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ gcd(m, n) = 1 ∧ ¬ m | n0 → ¬ m | n * n0
Rule argument
spec: nat-prime inst: name: gcd-div-one-01 seq: ⊦ gcd(m, n) = 1 ∧ ¬ m | n0 → ¬ m | n * n0 subst: [n0, n, m] → [n0, n, m] flags: rewrite, current
Additional information
Used terms: n0, n, m