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Proof step 13 from proof divi-same (previous step)

m0 < n, m * n1 = dist(n0, m0), m * n2 = n - m0, m0 < n ⊦ n = 0, m | dist(n, n0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 14:
n = n3 + m0 ∧ m0 ≤ n, m0 < n, m * n1 = dist(n0, m0), m * n2 = n3, m0 < n ⊦ n = 0, m | dist(n, n0)

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, m0, n3] flags:

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, m0, n3