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Proof step 15 from proof divi-same (previous step)

m * n1 = dist(n0, m0) ⊦ m * n2 + m0 = 0, m = 0, n2 = 0, m | dist(m * n2 + m0, n0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ m ≤ n → dist(m, n) = n - m
Proof step 17:
¬ n0 ≤ m0, m * n1 = dist(n0, m0) ⊦ m * n2 + m0 = 0, m = 0, n2 = 0, m | dist(m * n2 + m0, n0)
Proof step 21:
n0 ≤ m0, m * n1 = m0 - n0 ⊦ m * n2 + m0 = 0, m = 0, n2 = 0, m | dist(m * n2 + m0, n0)

Rule argument

spec: nat-prime inst: name: dist-fst seq: ⊦ m ≤ n → dist(m, n) = n - m subst: [n, m] → [m0, n0] flags: rewrite, current

Additional information

Used terms: m0, n0