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Proof step 22 from proof divi-same (previous step)

n ≤ m0, m * n1 = dist(n0, m0), m * n2 = m0 - n ⊦ m | dist(n, n0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 23:
m0 = n3 + n, n ≤ m0, m * n1 = dist(n0, m0), m * n2 = n3 ⊦ m | dist(n, n0)

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m0, n, n3] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m0, n, n3