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Proof step 48 from proof divi-same (previous step)

n ≤ n0, m * n2 + n = m * n1 + n0 ⊦ m | n0 - n

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 49:
n0 = n3 + n, n ≤ n0, m * n2 + n = m * n1 + n0 ⊦ m | n3

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n0, n, n3] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n0, n, n3