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Proof step 5 from proof divi-same (previous step)

m * n1 = dist(n0, m0), m | dist(n, m0) ⊦ m | dist(n, n0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ m | n ↔ (∃ n0. m * n0 = n)
Proof step 7:
m * n1 = dist(n0, m0), ∃ n0. m * n0 = dist(n, m0) ⊦ m | dist(n, n0)

Rule argument

spec: nat-prime inst: name: Divides seq: ⊦ m | n ↔ (∃ n0. m * n0 = n) subst: [n, m] → [dist(n, m0), m] flags: rewrite, current

Additional information

Used terms: dist(n, m0), m