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Proof step 53 from proof divi-same (previous step)
| m * n2 = m * n1 + n3 ⊦ m * (n2 - n1) = n3 |
User applied rule insert elim lemma
And obtained the following new goals
- Proof step 54:
m * n2 = m * n1 + n3 ⊦ n1 ≤ n2, m * (n2 - n1) = n3
- Proof step 56:
n2 = n0 + n1 ∧ n1 ≤ n2, m * n2 = m * n1 + n3 ⊦ m * n0 = n3
Rule argument
spec: nat
inst:
name: elim-sub
seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n
subst: [m, n, n0] → [n2, n1, n]
flags: Additional information
Used simplifier rules:
n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim)
Used terms: n2, n1, n