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Proof step 5 from proof divi-two-01 (previous step)

⊦ (∃ n0. 2 * n0 = m + 2) ↔ (∃ n0. 2 * n0 = m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
2 * n = m + 2 ⊦ ∃ n0. 2 * n0 = m

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%coef-17: ⊦ m * n + n = m1 * n ↔ ¬ ¬(m + 1 = m1 ∨ n = 0); from specification nat-mult