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Proof step 1 from proof gcd-div-03 (conclusion)

⊦ gcd(m, gcd(n, n0)) | n

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ n0 | gcd(m, n) → n0 | n
Proof step 3:
gcd(m, gcd(n, n0)) | gcd(n, n0) → gcd(m, gcd(n, n0)) | n0 ⊦ gcd(m, gcd(n, n0)) | n

Rule argument

spec: nat-prime inst: name: gcd-div-01 seq: ⊦ n0 | gcd(m, n) → n0 | n subst: [n0, m, n] → [gcd(m, gcd(n, n0)), n, n0] flags: current, []

Additional information

Used terms: gcd(m, gcd(n, n0)), n, n0