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Proof step 2 from proof gcd-div-one-01 (previous step)

gcd(m, n) = 1, m | n * n0 ⊦ m | n0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: nat-prime inst: name: gcd-div-one seq: ⊦ gcd(m, n) = 1 ∧ m | n * n0 → m | n0 subst: [m, n, n0] → [m, n, n0] flags: rewrite, current

Additional information

Used terms: m, n, n0