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Proof step 2 from proof gcd-eq (previous step)

gcd(m, n) = m, n < m ⊦ m = 0, n = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ m ≠ 0 → gcd(m, n) ≤ m
Proof step 4:
n ≠ 0 → gcd(n, m) ≤ n, gcd(m, n) = m, n < m ⊦ m = 0, n = 0

Rule argument

spec: nat-prime inst: name: gcd-le seq: ⊦ m ≠ 0 → gcd(m, n) ≤ m subst: [m, n] → [n, m] flags: current, []

Additional information

Used terms: n, m