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Proof step 8 from proof gcd-le-both (previous step)

n < m ⊦ m = n, n = 0, m = 0, gcd(m, n) ≤ m ∧ gcd(m, n) ≤ n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ gcd(m, n) = gcd(n, m)
Proof step 10:
n < m ⊦ m = n, n = 0, m = 0, gcd(n, m) ≤ m ∧ gcd(n, m) ≤ n

Rule argument

spec: nat-prime inst: name: gcd-c seq: ⊦ gcd(m, n) = gcd(n, m) subst: [n, m] → [n, m] flags: rewrite, current

Additional information

Used terms: n, m