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Proof step 1 from proof gcd-multdiv (conclusion)

⊦ gcd(m, n) | m * n0

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ gcd(m, n) | m
Proof step 3:
gcd(m, n) | m ⊦ gcd(m, n) | m * n0

Rule argument

spec: nat-prime inst: name: gcd-divs seq: ⊦ gcd(m, n) | m subst: [m, n] → [m, n] flags: current, []

Additional information

Used terms: m, n