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Proof step 5 from proof gcd-trans (previous step)

n0 | n ⊦ gcd(m, n0) | gcd(m, n), gcd(m, n0) | n

User applied rule insert lemma

And obtained the following new goals

Proof step 6:
⊦ n0 | m ∧ m | n → n0 | n
Proof step 7:
gcd(m, n0) | n0 ∧ n0 | n → gcd(m, n0) | n, n0 | n ⊦ gcd(m, n0) | gcd(m, n), gcd(m, n0) | n

Rule argument

spec: nat-prime inst: name: divi-trans seq: ⊦ n0 | m ∧ m | n → n0 | n subst: [n0, m, n] → [gcd(m, n0), n0, n] flags: current, []

Additional information

Used terms: gcd(m, n0), n0, n