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Proof step 3 from proof gcd-twice (previous step)

n ≤ 2 * n ⊦ gcd(n, 2 * n - n) = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ gcd(n, 2 * n - n) = n

Rule argument

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%twole-02: ⊦ m ≤ 2 * m; from specification nat-mult