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Proof step 1 from proof gcd-zero-01-h (conclusion)

m < n, gcd(m, n) = 0 ⊦ m = 0 ∧ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
gcd(m, n) = 0, m < n ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1