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Proof step 1 from proof gcdex (conclusion)

⊦ ∃ m0, n0. m * m0 + gcd(m, n) = n * n0 ∨ n * n0 + gcd(m, n) = m * m0

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
n ≤ m ⊦ ∃ m0, n0. m * m0 + gcd(m, n) = n * n0 ∨ n * n0 + gcd(m, n) = m * m0
Proof step 3:
⊦ n ≤ m, ∃ m0, n0. m * m0 + gcd(m, n) = n * n0 ∨ n * n0 + gcd(m, n) = m * m0

Rule argument

spec: nat-prime inst: name: gcdexh seq: n ≤ m ⊦ ∃ m0, n0. m * m0 + gcd(m, n) = n * n0 ∨ n * n0 + gcd(m, n) = m * m0 subst: [n, m] → [n, m] flags: current, []

Additional information

Used terms: n, m