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Proof step 6 from proof gcdnex-prime (
previous step
)
¬(∃ n. n ≠ 0 ∧ n ≠ 1 ∧ n | m ∧ n | m0) ⊦ ¬(∃ n. prime(n) ∧ n ≠ 0 ∧ n ≠ 1 ∧ n | m ∧ n | m0), m = 1, m0 = 1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
prime(n), n | m, n | m0 ⊦ n = 1, n = 0, m = 1, m0 = 1, ∃ n. n ≠ 0 ∧ n ≠ 1 ∧ n | m ∧ n | m0
Rule argument
Additional information