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Proof step 4 from proof mod2 (previous step)

2 ≠ 0, ∃ n0. m = n0 * 2, prime(m) ⊦ m = 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
prime(n * 2) ⊦ n = 1

Rule argument

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%twoeq: ⊦ 2 = 2 * n ↔ n = 1; from specification nat-mult