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Proof step 10 from proof modprime (
previous step
)
∀ m. 2 ≤ m ∧ m < n → n % m ≠ 0 ⊦ ∀ m. m | n → m = 1 ∨ m = n, n = 1, n = 0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 11
:
m | n, ∀ m. 2 ≤ m ∧ m < n → n % m ≠ 0 ⊦ m = 1, m = n, n = 1, n = 0
Rule argument
Additional information