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Proof step 5 from proof mult (previous step)

∀ m0. m0 | m * n → m0 = 1 ∨ m0 = m * n ⊦ n = 1, m = 1, m * n = 1, m = 0, n = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: m

Additional information

Used simplifier rules: divi-mult: ⊦ m | m * n0;%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult%one-02: ⊦ m0 ≠ 1 → (m0 * m = m ↔ m = 0); from specification nat-mult Used terms: m