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Proof step 7 from proof not-prime (previous step)

m * m ≤ n, 2 ≤ n, m | n, ∀ n0. n0 < n → ¬ prime(n0) ∧ 2 ≤ n0 → (∃ m. m | n0 ∧ prime(m) ∧ m * m ≤ n0) ⊦ n = 0, m = 1, m = n, n = 1, ∃ m. m | n ∧ prime(m) ∧ m * m ≤ n

User applied rule exists right

And obtained the following new goals

Proof step 8:
m * m ≤ n, 2 ≤ n, m | n, ∀ n0. n0 < n → ¬ prime(n0) ∧ 2 ≤ n0 → (∃ m. m | n0 ∧ prime(m) ∧ m * m ≤ n0) ⊦ n = 0, m = 1, m = n, n = 1, m | n ∧ prime(m) ∧ m * m ≤ n, ∃ m. m | n ∧ prime(m) ∧ m * m ≤ n

Rule argument

pos: right 5 terms: m abort: F discard: F computed: T

Additional information

Used terms: m