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Proof step 5 from proof twodiv-02 (previous step)

∀ m0. m0 | m → m0 = 1 ∨ m0 = m ⊦ m = 1, m = 0, m = 2, 2 | m + 1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: 2

Additional information

Used simplifier rules: divi-two-03: ⊦ ¬ 2 | n → 2 | n + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: 2