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Proof step 3 from proof add-ls-right2-le (previous step)

m0 + n0 ≤ m0 + n1, m < m0 + n0, n0 ≤ n1, m0 + n1 ≤ m ⊦ m0 + n0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
m0 + n0 ≤ m0 + n1, m < m0 + n0, n0 ≤ n1, m0 + n1 ≤ m ⊦ m0 + n0 ≤ m, m0 + n0 = 0

Rule argument

fma: m0 + n0 ≤ m

Additional information

Used simplifier rules: ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); Used formulas: m0 + n0 ≤ m