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Proof step 7 from proof elim-sub (previous step)

n0 = m - 1 + n1 ↔ m - 1 = n0 + n1, n1 < m ⊦ n0 = m - n1 + 1 ↔ m = n0 + n1 + 1, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
m - 1 = (m - 1 + n1) + n1, n1 < m ⊦ m = (m - 1 + n1) + n1 + 1, m = 0

Rule argument

Additional information

Used simplifier rules: num-01: ⊦ n + 1 - 1 = n;%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2