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Proof step 1 from proof fle (conclusion)

⊦ m < n ∧ n ≤ n0 → m < n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m < n, n ≤ n0, n0 ≤ m ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1