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Proof step 5 from proof fle (previous step)

m < n, n ≤ n0, n0 ≤ m, ¬ m < n0 → ¬ n < n0 ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ ¬ m ≤ n ↔ n < m
Proof step 7:
m < n, n ≤ n0, ¬ m < n0, ¬ m < n0 → ¬ n < n0 ⊦ n = 0

Rule argument

spec: nat inst: name: lels-01 seq: ⊦ ¬ m ≤ n ↔ n < m subst: [n, m] → [m, n0] flags: rewrite, current

Additional information

Used terms: m, n0