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Proof step 2 from proof l-num-02 (previous step)

n0 < n ⊦ m + n < m0 + n0 ↔ m + (n - n0) < m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 < n ⊦ m + n < m0 + n0 ↔ m + (n - n0) < m0, n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1