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Proof step 4 from proof le-add-02 (previous step)

n < m, n0 < m0, ∃ n1. (m + m0) + n1 = n + n0 + 1 ⊦ m = 0, m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
(m + m0) + n1 = n + n0 + 1, n < m, n0 < m0 ⊦ m = 0, m0 = 0

Rule argument

Additional information