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Proof step 6 from proof le-addex (previous step)

m < n ⊦ n = 0, ∃ n0. m + n0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
m < n ⊦ n = 0, ∃ n0. m + n0 = n

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1