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Proof step 1 from proof le-num-05 (conclusion)
n < n0 ⊦ m + (* n) ≤ (* n0) ↔ m ≤ n0 - n
Special step normalize
And obtained the following new goals
Proof step 2
:
n < n0 ⊦ m + n ≤ n0 ↔ m ≤ n0 - n