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Proof step 7 from proof le-sum (previous step)

n ≤ n0, n1 ≤ m0 + 1, m0 + n0 + 1 < n + n1, ∀ n, n0, n1. n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0 ⊦ n + n1 = 0

User applied rule all left

And obtained the following new goals

Proof step 8:
n ≤ n0, n1 ≤ m0 + 1, m0 + n0 + 1 < n + n1, n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0, ∀ n, n0, n1. n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0 ⊦ n + n1 = 0

Rule argument

pos: left 4 terms: n, n0, n1 abort: F discard: F computed: F

Additional information

Used terms: n, n0, n1