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Proof step 1 from proof lels-04 (conclusion)

⊦ n + m ≤ m0 → ¬ n0 + m0 < m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n0 + m0 < m, n + m ≤ m0 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1