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Proof step 2 from proof lep-02 (previous step)

⊦ m + n ≤ m + n0 ↔ n ≤ n0

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: n

Additional information

Used simplifier rules: lep: ⊦ m ≤ m + n;%lez: ⊦ 0 ≤ m;%succ-01: ⊦ m + 1 ≤ n ↔ m < n;%nat freely generated by 0, +1;;%succ: ⊦ m +1 = m + 1; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%l: ⊦ m + n < m + n0 ↔ n < n0; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%add-base: ⊦ n + 0 = n; from specification nat-basic2