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Proof step 1 from proof ls-07 (conclusion)

n ≤ m, n0 ≤ m ⊦ m - n < m - n0 ↔ n0 < n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ m, n0 ≤ m ⊦ m < (m - n0) + n ↔ n0 < n

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ m ≤ n ↔ n < m;%le-ls-simp: ⊦ m ≤ n → (n < m ↔ false);%ls-01: n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0;