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Proof step 1 from proof pls (conclusion)

m ≤ m0, n < n0 ⊦ m + n < m0 + n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m ≤ m0, n < n0, m0 + n0 ≤ m + n ⊦ n0 = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1