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Proof step 1 from proof prop-01 (conclusion)
n ≤ m ⊦ (m - n) + n = m
Heuristic elimination applied rule insert elim lemma
And obtained the following new goals
Proof step 2
:
n ≤ m ⊦ n0 = m - n ↔ m = n0 + n
Rule argument
spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m, n, n0] flags: rewrite, current
Additional information
Used terms: m, n, n0